sqlite/SOURCES/sqlite-3.26.0-CVE-2019-1992...

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From 7d47517d579601bb6e59e33bf0896f0ed36aa0aa Mon Sep 17 00:00:00 2001
From: Ondrej Dubaj <odubaj@redhat.com>
Date: Mon, 20 Jan 2020 09:34:41 +0100
Subject: [PATCH] Continue to back away from the LEFT JOIN optimization of
check-in
by disallowing query flattening if the outer query is DISTINCT. Without this fix,
if an index scan is run on the table within the view on the right-hand side of the
LEFT JOIN, stale result registers might be accessed yielding incorrect results,
and/or an OP_IfNullRow opcode might be invoked on the un-opened table, resulting
in a NULL-pointer dereference. This problem was found by the Yongheng and Rui fuzzer.
---
src/select.c | 8 ++++++--
test/join.test | 13 +++++++++++++
2 files changed, 19 insertions(+), 2 deletions(-)
diff --git a/src/select.c b/src/select.c
index c60ff27..0205a08 100644
--- a/src/select.c
+++ b/src/select.c
@@ -3569,6 +3569,7 @@ static void substSelect(
** (3b) the FROM clause of the subquery may not contain a virtual
** table and
** (3c) the outer query may not be an aggregate.
+** (3d) the outer query may not be DISTINCT.
**
** (4) The subquery can not be DISTINCT.
**
@@ -3765,8 +3766,11 @@ static int flattenSubquery(
*/
if( (pSubitem->fg.jointype & JT_OUTER)!=0 ){
isLeftJoin = 1;
- if( pSubSrc->nSrc>1 || isAgg || IsVirtual(pSubSrc->a[0].pTab) ){
- /* (3a) (3c) (3b) */
+ if( pSubSrc->nSrc>1 /* (3a) */
+ || isAgg /* (3b) */
+ || IsVirtual(pSubSrc->a[0].pTab) /* (3c) */
+ || (p->selFlags & SF_Distinct)!=0 /* (3d) */
+ ){
return 0;
}
}
diff --git a/test/join.test b/test/join.test
index 8c6f463..8c6a53d 100644
--- a/test/join.test
+++ b/test/join.test
@@ -844,4 +844,17 @@ do_execsql_test join-15.110 {
ORDER BY a1, a2, a3, a4, a5;
} {1 {} {} {} {} 1 11 {} {} {} 1 12 {} {} {} 1 12 121 {} {} 1 13 {} {} {}}
+# 2019-12-18 problem with a LEFT JOIN where the RHS is a view.
+# Detected by Yongheng and Rui.
+# Follows from the optimization attempt of check-in 41c27bc0ff1d3135
+# on 2017-04-18
+#
+reset_db
+do_execsql_test join-22.10 {
+ CREATE TABLE t0(a, b);
+ CREATE INDEX t0a ON t0(a);
+ INSERT INTO t0 VALUES(10,10),(10,11),(10,12);
+ SELECT DISTINCT c FROM t0 LEFT JOIN (SELECT a+1 AS c FROM t0) ORDER BY c ;
+} {11}
+
finish_test
--
2.19.1