Resolves: #1890442 - make the code compile against python-3.10.0a1
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0001-python-pycurl-7.43.0.6-python-3.10.patch
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0001-python-pycurl-7.43.0.6-python-3.10.patch
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From b3a1ff559c28f71702248cae317fa83baaa086a0 Mon Sep 17 00:00:00 2001
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From: Kamil Dudka <kdudka@redhat.com>
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Date: Mon, 26 Oct 2020 17:26:23 +0100
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Subject: [PATCH] src/module.c: make the code compile against python-3.10.0a1
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src/module.c:353:25: error: lvalue required as left operand of assignment
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353 | Py_TYPE(&Curl_Type) = &PyType_Type;
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| ^
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src/module.c:354:30: error: lvalue required as left operand of assignment
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354 | Py_TYPE(&CurlMulti_Type) = &PyType_Type;
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| ^
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src/module.c:355:30: error: lvalue required as left operand of assignment
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355 | Py_TYPE(&CurlShare_Type) = &PyType_Type;
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| ^
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Bug: https://bugzilla.redhat.com/1890442
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Upstream-commit: c4036bdcb5dd01420a451cf02efac7c3fdf9e41f
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Signed-off-by: Kamil Dudka <kdudka@redhat.com>
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---
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src/module.c | 12 +++++++++---
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1 file changed, 9 insertions(+), 3 deletions(-)
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diff --git a/src/module.c b/src/module.c
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index 65e8c3a..9204ee0 100644
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--- a/src/module.c
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+++ b/src/module.c
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@@ -11,6 +11,12 @@
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#define PYCURL_VERSION_PREFIX "PycURL/" PYCURL_VERSION_STRING
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+/* needed for compatibility with python < 3.10, as suggested at:
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+ * https://docs.python.org/3.10/whatsnew/3.10.html#id2 */
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+#if PY_VERSION_HEX < 0x030900A4
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+# define Py_SET_TYPE(obj, type) ((Py_TYPE(obj) = (type)), (void)0)
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+#endif
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+
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PYCURL_INTERNAL char *empty_keywords[] = { NULL };
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PYCURL_INTERNAL PyObject *bytesio = NULL;
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@@ -412,9 +418,9 @@ initpycurl(void)
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p_Curl_Type = &Curl_Type;
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p_CurlMulti_Type = &CurlMulti_Type;
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p_CurlShare_Type = &CurlShare_Type;
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- Py_TYPE(&Curl_Type) = &PyType_Type;
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- Py_TYPE(&CurlMulti_Type) = &PyType_Type;
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- Py_TYPE(&CurlShare_Type) = &PyType_Type;
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+ Py_SET_TYPE(&Curl_Type, &PyType_Type);
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+ Py_SET_TYPE(&CurlMulti_Type, &PyType_Type);
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+ Py_SET_TYPE(&CurlShare_Type, &PyType_Type);
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/* Create the module and add the functions */
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if (PyType_Ready(&Curl_Type) < 0)
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--
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2.25.4
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@ -16,7 +16,7 @@
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Name: python-%{modname}
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Name: python-%{modname}
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Version: 7.43.0.6
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Version: 7.43.0.6
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Release: 1%{?dist}
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Release: 2%{?dist}
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Summary: A Python interface to libcurl
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Summary: A Python interface to libcurl
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License: LGPLv2+ or MIT
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License: LGPLv2+ or MIT
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@ -25,6 +25,9 @@ URL: http://pycurl.sourceforge.net/
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# Source0: https://dl.bintray.com/pycurl/pycurl/pycurl-%%{version}.tar.gz
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# Source0: https://dl.bintray.com/pycurl/pycurl/pycurl-%%{version}.tar.gz
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Source0: https://github.com/pycurl/pycurl/archive/REL_7_43_0_6.tar.gz#/pycurl-%{version}.tar.gz
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Source0: https://github.com/pycurl/pycurl/archive/REL_7_43_0_6.tar.gz#/pycurl-%{version}.tar.gz
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# make the code compile against python-3.10.0a1 (#1890442)
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Patch1: 0001-python-pycurl-7.43.0.6-python-3.10.patch
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# drop link-time vs. run-time TLS backend check (#1446850)
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# drop link-time vs. run-time TLS backend check (#1446850)
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Patch2: 0002-python-pycurl-7.43.0-tls-backend.patch
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Patch2: 0002-python-pycurl-7.43.0-tls-backend.patch
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@ -166,6 +169,9 @@ rm -fv tests/fake-curl/libcurl/*.so
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%endif
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%endif
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%changelog
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%changelog
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* Tue Oct 27 2020 Kamil Dudka <kdudka@redhat.com> - 7.43.0.6-2
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- make the code compile against python-3.10.0a1 (#1890442)
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* Thu Sep 03 2020 Kamil Dudka <kdudka@redhat.com> - 7.43.0.6-1
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* Thu Sep 03 2020 Kamil Dudka <kdudka@redhat.com> - 7.43.0.6-1
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- update to 7.43.0.6
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- update to 7.43.0.6
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