Remove usage of parser module, deprecated in Python 3.9
Resolves https://bugzilla.redhat.com/show_bug.cgi?id=1787902
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f606fef19d035719be6ed862f7f426a0e7c582e1.patch
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f606fef19d035719be6ed862f7f426a0e7c582e1.patch
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From 24898e06404fdade3c37c9229402ea817d068e75 Mon Sep 17 00:00:00 2001
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From: Bruno Oliveira <nicoddemus@gmail.com>
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Date: Sun, 5 Jan 2020 14:15:51 -0300
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Subject: [PATCH] Remove usage of parser module, deprecated in Python 3.9
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Fix #6404
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---
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changelog/6404.trivial.rst | 1 +
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src/_pytest/_code/source.py | 9 ++-------
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2 files changed, 3 insertions(+), 7 deletions(-)
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create mode 100644 changelog/6404.trivial.rst
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diff --git a/changelog/6404.trivial.rst b/changelog/6404.trivial.rst
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new file mode 100644
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index 0000000000..8252098b6a
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--- /dev/null
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+++ b/changelog/6404.trivial.rst
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@@ -0,0 +1 @@
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+Remove usage of ``parser`` module, deprecated in Python 3.9.
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diff --git a/src/_pytest/_code/source.py b/src/_pytest/_code/source.py
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index c8a4b6adf3..b35e97b9ce 100644
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--- a/src/_pytest/_code/source.py
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+++ b/src/_pytest/_code/source.py
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@@ -123,18 +123,13 @@ def isparseable(self, deindent=True):
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""" return True if source is parseable, heuristically
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deindenting it by default.
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"""
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- from parser import suite as syntax_checker
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-
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if deindent:
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source = str(self.deindent())
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else:
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source = str(self)
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try:
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- # compile(source+'\n', "x", "exec")
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- syntax_checker(source + "\n")
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- except KeyboardInterrupt:
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- raise
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- except Exception:
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+ ast.parse(source)
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+ except (SyntaxError, ValueError, TypeError):
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return False
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else:
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return True
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@ -6,6 +6,9 @@ License: MIT
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URL: https://pytest.org
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Source0: %{pypi_source}
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# Remove usage of parser module, deprecated in Python 3.9
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Patch1: https://github.com/pytest-dev/pytest/commit/f606fef19d035719be6ed862f7f426a0e7c582e1.patch
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# The test in this specfile use pytest-timeout
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# When building pytest for the first time with new Python version
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# that is not possible as it depends on pytest
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