55 lines
1.8 KiB
Plaintext
55 lines
1.8 KiB
Plaintext
%__kmod_path ^/lib/modules/.*/(modules.builtin|.*\.ko|.*\.ko\.gz|.*\.ko\.bz2|.*\.ko\.xz|.*\.ko\.zst)$
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# Notes on Lua:
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# The backslash in strings (like "\n" newline) needs to be doubled
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# because we are inside rpm macro. Single backslashes before most chars
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# disappear (removed by rpm's parser), so "\n" turns into just "n".
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# In string.gsub patterns, unlike regexps, backslash has no special meaning.
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# It can't escape . and such. (Use one-character set [.] to represent
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# literal period, or lua's percent escape: %.)
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# Pipe (|) has no special meaning too.
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%__kmod_provides() %{lua:
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function basename(fn)
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local b = string.gsub(fn, ".*/", "")
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-- the above adjusts gsub() result to 1 value
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-- "return f()" construct would return _all_ values, two in case of gsub()
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return b
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end
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function strip_compress_sfx(fn)
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local cnt
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fn, cnt = string.gsub(fn, "%.gz$", "")
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if cnt == 1 then return fn; end
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fn, cnt = string.gsub(fn, "%.bz2$", "")
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if cnt == 1 then return fn; end
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fn, cnt = string.gsub(fn, "%.xz$", "")
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if cnt == 1 then return fn; end
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fn, cnt = string.gsub(fn, "%.zst$", "")
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return fn
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end
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function printdep(mod)
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print("kmod("..mod..") ")
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end
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local fn = rpm.expand("%1")
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local bn = basename(fn)
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if bn == "modules.builtin" then
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for l in io.lines(fn) do
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local builtin_mod = basename(l)
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printdep(builtin_mod)
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local nocompr = strip_compress_sfx(builtin_mod)
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if nocompr ~= builtin_mod then
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printdep(nocompr)
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end
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end
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else
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local mod = string.match(bn, "%g+%.ko")
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if mod then
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printdep(mod)
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local nocompr = strip_compress_sfx(mod)
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if nocompr ~= mod then
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printdep(nocompr)
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end
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end
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end
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}
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